Which of the following orders is not correct | vedclass

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(B) Let us analyze each option:$1$. First ionisation enthalpy: The order is $N > O > P > S$. Nitrogen $(2p^3)$ has a stable half-filled configuration,

Vedclass · Accepted Answer

$F > Cl > O > S$ - Negative electron gain enthalpy

Vedclass · Answer

(B) Let us analyze each option:$1$. First ionisation enthalpy: The order is $N > O > P > S$. Nitrogen $(2p^3)$ has a stable half-filled configuration,making its $IE_1$ higher than Oxygen $(2p^4)$. Similarly,Phosphorus $(3p^3)$ is higher than Sulfur $(3p^4)$. Across the period,$N > O$ and $P > S$,and down the group $N > P$ and $O > S$. Thus,$N > O > P > S$ is correct.$2$. Negative electron gain enthalpy: The correct order is $Cl > F > S > O$. Chlorine has a higher electron gain enthalpy than Fluorine due to inter-electronic repulsion in the small $2p$ orbital of Fluorine. Similarly,Sulfur is higher than Oxygen. The given order $F > Cl > O > S$ is incorrect.$3$. Size: For the same element in different oxidation states,the size decreases as the positive charge increases. Thus,$Fe^{3+} $4$. Non-metallic character: Non-metallic character increases across a period and decreases down a group. $O$ and $N$ are more non-metallic than $S$ and $P$. Among $O$ and $N$,$O$ is more electronegative/non-metallic. Thus,$O > N > S > P$ is correct.Therefore,the incorrect order is option $B$.

Which of the following orders is not correct about the property shown against it?

Similar Questions

The electronic configurations of four elements are:
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$IV. [Ar] \, 3d^7 \, 4s^2$
Select the incorrect statement about these elements.

In which of the following arrangements,the sequence does not strictly follow the property indicated against it?

Which of the following orders is not correct for the given property?

In which of the following arrangements is the order $NOT$ according to the property indicated against it?

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