Which of the following pairs has a similar ma | vedclass

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(B) The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.
For $Fe^{3+

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$Fe^{3+}, Mn^{2+}$

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(B) The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.
For $Fe^{3+}$ $(Z=26)$: The electronic configuration is $[Ar] 3d^5$. The number of unpaired electrons $(n)$ = $5$.
For $Mn^{2+}$ $(Z=25)$: The electronic configuration is $[Ar] 3d^5$. The number of unpaired electrons $(n)$ = $5$.
Since both $Fe^{3+}$ and $Mn^{2+}$ have $5$ unpaired electrons,they have the same magnetic moment of $\sqrt{5(5+2)} = \sqrt{35} \ BM$.

Which of the following pairs has a similar magnetic moment?

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