Which of the following pairs of compounds con | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} (V - N)$,where $V$ is the number of

Vedclass · Accepted Answer

$BrF_5$ and $XeF_6$

Vedclass · Answer

(A) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} (V - N)$,where $V$ is the number of valence electrons of the central atom and $N$ is the number of bonding electrons (monovalent atoms attached).$A$: $BrF_5$ ($Br$ has $7$ valence $e^-$,$5$ bonded $F$ atoms): $	ext{Lone pairs} = \frac{1}{2} (7 - 5) = 1$. $XeF_6$ ($Xe$ has $8$ valence $e^-$,$6$ bonded $F$ atoms): $	ext{Lone pairs} = \frac{1}{2} (8 - 6) = 1$.$B$: $ICl$ ($I$ has $7$ valence $e^-$,$1$ bonded $Cl$ atom): $	ext{Lone pairs} = \frac{1}{2} (7 - 1) = 3$. $H_2S$ ($S$ has $6$ valence $e^-$,$2$ bonded $H$ atoms): $	ext{Lone pairs} = \frac{1}{2} (6 - 2) = 2$.$C$: $ClF_3$ ($Cl$ has $7$ valence $e^-$,$3$ bonded $F$ atoms): $	ext{Lone pairs} = \frac{1}{2} (7 - 3) = 2$. $XeF_2$ ($Xe$ has $8$ valence $e^-$,$2$ bonded $F$ atoms): $	ext{Lone pairs} = \frac{1}{2} (8 - 2) = 3$.$D$: $IF_7$ ($I$ has $7$ valence $e^-$,$7$ bonded $F$ atoms): $	ext{Lone pairs} = \frac{1}{2} (7 - 7) = 0$. $XeF_4$ ($Xe$ has $8$ valence $e^-$,$4$ bonded $F$ atoms): $	ext{Lone pairs} = \frac{1}{2} (8 - 4) = 2$.Thus,$BrF_5$ and $XeF_6$ both have $1$ lone pair on their central atoms.

List-$I$	List-$II$
$A. XeF_4$	$I. See-saw$
$B. SF_4$	$II. Square planar$
$C. NH_4^{+}$	$III. Bent T-shaped$
$D. BrF_3$	$IV. Tetrahedral$

Which of the following pairs of compounds consists of an equal number of lone pairs of electrons in the valence shell of the central atom?

Similar Questions

The number of lone pairs of electrons present on $Xe$ in $XeF_4$ is

Which molecule is linear?

Match List-$I$ with List-$II$:
List-$I$ List-$II$
$A. XeF_4$ $I. See-saw$
$B. SF_4$ $II. Square planar$
$C. NH_4^{+}$ $III. Bent T-shaped$
$D. BrF_3$ $IV. Tetrahedral$

Choose the correct answer from the options given below:

$XeF_2$ molecule is

Which of the following species/molecules does not have the same number of bond pairs and lone pairs?

Vedclass Test Series

Exam Paper Generator

Online Exam Module