Which of the following pairs will diffuse at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$ of the gas

Vedclass · Accepted Answer

$NO$,$C_2H_6$

Vedclass · Answer

(D) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$ of the gas: $r \propto \frac{1}{\sqrt{M}}$.Two gases will diffuse at the same rate if they have the same molar mass.For option $(D)$: $M_{NO} = 14 + 16 = 30 \ g/mol$ and $M_{C_2H_6} = (2 	imes 12) + (6 	imes 1) = 30 \ g/mol$.Since both $NO$ and $C_2H_6$ have the same molecular weight of $30 \ g/mol$,they will diffuse at the same rate.

Which of the following pairs will diffuse at the same rate through a porous plug?

Similar Questions

The rms velocity of hydrogen is $\sqrt{7}$ times the rms velocity of nitrogen. If $T$ is the temperature of the gas,which of the following is true?

Which of the following gases will have the lowest root mean square speed at $25\,^{\circ}C$?

The r.m.s. velocity of $CO_2$ at a temperature $T$ (in kelvin) is $x \ cm \ s^{-1}$. At what temperature (in kelvin), the r.m.s. velocity of nitrous oxide would be $4 x \ cm \ s^{-1}$ (in $T$)? (Atomic weights of $C, N$ and $O$ are respectively $12, 14$ and $16$)

Initially,the root mean square $(rms)$ velocity of $N_2$ molecules at a certain temperature is $u$. If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms,then the new $rms$ velocity will be:

If the $u_{rms}$ value of a gas at $27\,^oC$ is $30\,R^{1/2}$,then the molar mass of the gas is ........... $kg/mol$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module