Which of the following potential energy curves in the figure cannot possibly describe the elastic collision of two billiard balls? Here $r$ is the distance between the centres of the balls.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) For an elastic collision between two hard billiard balls,the potential energy $V(r)$ must satisfy two conditions:
$1$. When the distance $r$ between the centers is greater than $2R$ (where $R$ is the radius of each ball),the balls do not interact,so the potential energy $V(r) = 0$.
$2$. When the distance $r$ is less than $2R$,the balls are in contact and undergo deformation,leading to a rapid increase in potential energy. At the point of contact $r = 2R$,the potential energy should be zero,and for $r < 2R$,it should be positive and increasing.
Looking at the given curves:
- Curve $(v)$ shows $V(r) = 0$ for $r \ge 2R$ and $V(r) > 0$ for $r < 2R$,which correctly describes the interaction.
- Curves $(i), (ii), (iii), (iv),$ and $(vi)$ do not satisfy these physical requirements. For example,$(ii)$ shows potential energy increasing with distance,which is incorrect,and $(i)$ and $(vi)$ show non-zero potential energy for $r > 2R$.
Therefore,the curves that cannot describe the elastic collision are $(i), (ii), (iii), (iv),$ and $(vi)$.

Explore More

Similar Questions

$A$ body of mass $30 \ kg$ moving with a velocity $20 \ ms^{-1}$ undergoes a one-dimensional elastic collision with another ball of the same mass moving in the opposite direction with a velocity of $30 \ ms^{-1}$. After the collision,the velocities of the first and second bodies respectively are:

Two identical balls $A$ and $B$ having velocities of $0.5 \, m s^{-1}$ and $-0.3 \, m s^{-1}$ respectively collide elastically in one dimension. The velocities of $B$ and $A$ after the collision respectively will be

$A$ sphere of mass $0.1\,kg$ is attached to a cord of $1\,m$ length. Starting from the height of its point of suspension,this sphere hits a block of the same mass at rest on a frictionless table. If the impact is elastic,then the kinetic energy of the block after the collision is ............. $J$.

Difficult
View Solution

If $n$ balls hit elastically and normally on a surface per unit time and all balls of mass $m$ are moving with the same velocity $u$, then the force on the surface is ..........

$A$ ball of mass $m$ moving with speed $v$ collides elastically with an identical stationary ball which is initially at rest. After collision,the first ball moves at an angle $\theta$ to its initial direction and has speed $(v/3)$. The second ball moves in a straight line after the collision. Then,the speed of the second ball after the collision is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo