Which of the following reacts with HBr at a f | vedclass

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(B) The reaction of alcohols with $HBr$ proceeds via an $S_{N}1$ mechanism,which involves the formation of a carbocation intermediate. The rate of the

Vedclass · Accepted Answer

$1-$Methylcyclohexanol

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(B) The reaction of alcohols with $HBr$ proceeds via an $S_{N}1$ mechanism,which involves the formation of a carbocation intermediate. The rate of the reaction depends on the stability of the carbocation formed.$(A)$ Cyclohexanol forms a $2^{\circ}$ carbocation.$(B)$ $1-$Methylcyclohexanol forms a $3^{\circ}$ carbocation.$(C)$ trans$-2-$Methylcyclohexanol forms a $2^{\circ}$ carbocation.$(D)$ cis$-2-$Methylcyclohexanol forms a $2^{\circ}$ carbocation.Since a $3^{\circ}$ carbocation is more stable than a $2^{\circ}$ carbocation,$1$-methylcyclohexanol reacts at a faster rate.

Which of the following reacts with $HBr$ at a faster rate?

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