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(D) $SO_2$ acts as a reducing agent in the presence of moisture.$(I)$ $SO_2$ reduces $O_3$ to $O_2$: $SO_2 + O_3 	o SO_3 + O_2$.$(II)$ $SO_2$ reduces

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$I, II, III$

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(D) $SO_2$ acts as a reducing agent in the presence of moisture.$(I)$ $SO_2$ reduces $O_3$ to $O_2$: $SO_2 + O_3 	o SO_3 + O_2$.$(II)$ $SO_2$ reduces acidic dichromate $(Cr_2O_7^{2-})$ to $Cr^{3+}$: $Cr_2O_7^{2-} + 3SO_2 + 2H^{+} 	o 2Cr^{3+} + 3SO_4^{2-} + H_2O$.$(III)$ $SO_2$ reduces acidic permanganate $(MnO_4^{-})$ to $Mn^{2+}$: $2MnO_4^{-} + 5SO_2 + 2H_2O 	o 2Mn^{2+} + 5SO_4^{2-} + 4H^{+}$.$(IV)$ $SO_2$ acts as an oxidizing agent towards $H_2S$: $SO_2 + 2H_2S 	o 3S + 2H_2O$. Thus,$H_2S$ is oxidized,not reduced.Therefore,$SO_2$ reduces $O_3$,$Cr_2O_7^{2-}$,and $MnO_4^{-}$. The correct option is $D$.

Which of the following reactants can be reduced by $SO_2$ in the given reactions?
$(I)$ $O_3 \to$ product
$(II)$ $Cr_2O_7^{2-} \xrightarrow{H^{+}} $ product
$(III)$ $MnO_4^{-} \xrightarrow{H^{+}} $ product
$(IV)$ $H_2S \to$ product

Similar Questions

Assertion $(A)$: Ferricyanide ion oxidises $H_2O_2$ to $H_2O$ in basic medium.
Reason $(R)$: Oxidation product of $H_2O_2$ is $O_2$. Which of the following is true?

Which of the following is oxidised by $SO_2$?

One litre of $0.15 \ M$ $Na_2SO_3$ aqueous solution is mixed with $500 \ mL$ of $0.2 \ M$ $K_2Cr_2O_7$ aqueous solution in acid medium. What is the number of moles of $K_2Cr_2O_7$ remaining in the solution after the reaction?

$100 \ mL$ of $0.1 \ M$ $Fe^{2+}$ solution was titrated with $\frac{1}{60} \ M$ $Cr_2O_7^{2-}$ solution in acid medium. What is the volume (in $L$) of $Cr_2O_7^{2-}$ solution consumed?

In the given equation,potassium dichromate acts as an oxidant in an acidic medium: $Cr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O$. The equivalent weight of $K_2Cr_2O_7$ is (Molecular weight $= M$):

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Which of the following reactants can be reduced by $SO_2$ in the given reactions?$(I)$ $O_3 \to$ product$(II)$ $Cr_2O_7^{2-} \xrightarrow{H^{+}} $ product$(III)$ $MnO_4^{-} \xrightarrow{H^{+}} $ product$(IV)$ $H_2S \to$ product