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(C) The Hoffmann Bromamide degradation reaction involves the conversion of an amide $(RCONH_2)$ to a primary amine $(RNH_2)$ using $Br_2$ and $NaOH$ (

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$C_6H_5CH_2COCH_3 \xrightarrow[iii) LiAlH_4, H_2O]{i) Br_2, NaOH/H^+, ii) NH_3/\Delta} C_6H_5CH_2CH_2NH_2$

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(C) The Hoffmann Bromamide degradation reaction involves the conversion of an amide $(RCONH_2)$ to a primary amine $(RNH_2)$ using $Br_2$ and $NaOH$ (or $KOH$).$A$. $C_6H_5CH_2CONH_2 + Br_2 + 4NaOH \rightarrow C_6H_5CH_2NH_2 + Na_2CO_3 + 2NaBr + 2H_2O$. This is a Hoffmann Bromamide degradation.$B$. $C_6H_5CN$ $\xrightarrow{KOH, H_2O} C_6H_5CONH_2$ $\xrightarrow{Br_2, NaOH} C_6H_5NH_2$. This involves Hoffmann Bromamide degradation in the second step.$C$. $C_6H_5CH_2COCH_3$ $\xrightarrow{Br_2, NaOH} C_6H_5CH_2COOH$ $\xrightarrow{NH_3, \Delta} C_6H_5CH_2CONH_2$ $\xrightarrow{LiAlH_4} C_6H_5CH_2CH_2NH_2$. The first step is a haloform reaction,and the final step is a reduction. This reaction does not involve Hoffmann Bromamide degradation.$D$. $C_6H_5COCl$ $\xrightarrow{NH_3} C_6H_5CONH_2$ $\xrightarrow{Br_2, NaOH} C_6H_5NH_2$. This involves Hoffmann Bromamide degradation in the second step.

Which of the following reactions does not involve the Hoffmann Bromamide degradation?

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