Which of the following reactions is correct?

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Question

(A) Option $A$ is correct. The reaction of $1-$methylcyclohexene with $HI$ follows Markovnikov's rule,where the nucleophile $(I^-)$ attaches to the mo

Vedclass · Accepted Answer

$1-$methylcyclohexene + $HI$ $\rightarrow$ $1-$iodo$-1-$methylcyclohexane (Markovnikov addition)

Vedclass · Answer

(A) Option $A$ is correct. The reaction of $1-$methylcyclohexene with $HI$ follows Markovnikov's rule,where the nucleophile $(I^-)$ attaches to the more substituted carbon atom of the double bond,resulting in $1-$iodo$-1-$methylcyclohexane. Option $B$ is incorrect because the reaction of cyclohexene with $Br_2$ in the presence of $UV$ light/heat typically leads to allylic bromination,not addition. Option $C$ represents the Hofmann bromamide degradation reaction,which is correctly balanced as: $CH_3CH_2CONH_2 + Br_2 + 4NaOH \rightarrow CH_3CH_2NH_2 + Na_2CO_3 + 2NaBr + 2H_2O$. Option $D$ represents the carbylamine reaction,which is also correctly written. Given the provided images,the question likely intends to identify the correct chemical transformation shown in the diagrams. Since both $A$ and $C$ are chemically correct,$A$ is the primary reaction depicted in the solution image.

Similar Questions

The compounds that will give an isomer of $2,2$-dimethylpropane on catalytic hydrogenation are:
$(1)$ $CH_3-CH=C(CH_3)_2$
$(2)$ $CH_3-CH=CH-CH_3$
$(3)$ $CH_3-CH=CH-CH_2-CH_3$
$(4)$ $CH_3-C(CH_3)=C(CH_3)-CH_3$

In the following reaction: $CH_3-C(CH_3)_2-CH=CH_2 \xrightarrow{H_2O/H^{+}} A + B$,the major product is:

In which of the following,addition of $HBr$ does not take place against Markownikoff's rule,or for which is the Anti-Markownikoff addition of $HBr$ not observed?

In alkene (ethene),the number of $sp^2$ hybridized carbon atoms is:

Propene,$CH_3-CH=CH_2$ can be converted to $1-propanol$ by oxidation. Which set of reagents among the following is ideal to effect the conversion?

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