Which of the following reactions will yield 2 | vedclass

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(B) The reaction of propyne $(CH_3C \equiv CH)$ with two equivalents of hydrogen bromide $(HBr)$ follows Markovnikov's rule. In the first step,$HBr$ a

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$CH_3C \equiv CH + 2HBr \rightarrow$

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(B) The reaction of propyne $(CH_3C \equiv CH)$ with two equivalents of hydrogen bromide $(HBr)$ follows Markovnikov's rule. In the first step,$HBr$ adds to the triple bond to form $2-$bromopropene $(CH_3C(Br)=CH_2)$. In the second step,another molecule of $HBr$ adds to the double bond,again following Markovnikov's rule,to yield $2, 2-$dibromopropane $(CH_3C(Br)_2CH_3)$.

Which of the following reactions will yield $2, 2-$dibromopropane?

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