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(C) Electron-withdrawing substituents (like halogens,$-NO_2$,$-C_6H_5$,etc.) disperse the negative charge,stabilize the carboxylate ion,and thus incre

Vedclass · Accepted Answer

$FCH_2COOH > ClCH_2COOH > BrCH_2COOH > CH_3COOH$

Vedclass · Answer

(C) Electron-withdrawing substituents (like halogens,$-NO_2$,$-C_6H_5$,etc.) disperse the negative charge,stabilize the carboxylate ion,and thus increase the acidity of the parent acid.Conversely,electron-releasing substituents intensify the negative charge,destabilize the carboxylate ion,and decrease the acidity.The electronegativity of halogens decreases in the order $F > Cl > Br$,which means the $-I$ (inductive) effect also decreases in the same order.Therefore,the correct order of acidity is $FCH_2COOH > ClCH_2COOH > BrCH_2COOH > CH_3COOH$.

Which of the following represents the correct order of the acidity in the given compounds?

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