Which of the following represents the given m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the hybridisation of carbon atoms,we count the number of sigma bonds and lone pairs attached to each carbon atom:$1$. $sp^3$ hybridis

Vedclass · Accepted Answer

$H_2C=CH-C\equiv N$

Vedclass · Answer

(A) To determine the hybridisation of carbon atoms,we count the number of sigma bonds and lone pairs attached to each carbon atom:$1$. $sp^3$ hybridisation: $4$ sigma bonds (tetrahedral geometry).$2$. $sp^2$ hybridisation: $3$ sigma bonds (trigonal planar geometry).$3$. $sp$ hybridisation: $2$ sigma bonds (linear geometry).Let's analyze option $A$: $H_2C=CH-C\equiv N$- The first carbon $(CH_2=)$ has $3$ sigma bonds $\rightarrow sp^2$.- The second carbon $(-CH-)$ has $3$ sigma bonds $\rightarrow sp^2$.- The third carbon $(-C\equiv)$ has $2$ sigma bonds $\rightarrow sp$.- The nitrogen atom is attached to the third carbon with a triple bond,and the carbon itself is $sp$ hybridised. The nitrogen atom in $C\equiv N$ is also $sp$ hybridised due to the triple bond and one lone pair.Thus,the sequence $sp^2-sp^2-sp-sp$ corresponds to $H_2C=CH-C\equiv N$.

Which of the following represents the given mode of hybridisation $sp^2-sp^2-sp-sp$ from left to right?

Similar Questions

In the structure $CH_2 = CH - C \equiv CH$,what are the hybridization states of the carbon atoms that are connected to each other by a single bond?

In the molecule $HC^{1} \equiv C^{2} - CH^{3} = CH^{4} - CH_{3}^{5}$,which carbon atom exhibits the lowest electronegativity?

Which of the following bonds is most acidic?

Which of the following compounds do not have $sp^3$ carbon atom$(s)$?
$I$. Acetone
$II$. Acetic acid
$III$. Buta-$1,3$-diene
$IV$. Propyne
$V$. Naphthalene

What is the hybridization shown by $C_1$ and $C_2$ carbons,respectively in the given compound? $OHC-CH=CH-CH_2-COOCH_3$

Vedclass Test Series

Exam Paper Generator

Online Exam Module