Which of the following sequence of reagents c | vedclass

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(A) The conversion of propene $(CH_3-CH=CH_2)$ to $1$-chloropropane $(CH_3-CH_2-CH_2-Cl)$ requires an anti-Markovnikov hydration followed by the conve

Vedclass · Accepted Answer

$(i) (BH_3)_2, (ii) H_2O_2 / OH^- ; HCl, ZnCl_2$

Vedclass · Answer

(A) The conversion of propene $(CH_3-CH=CH_2)$ to $1$-chloropropane $(CH_3-CH_2-CH_2-Cl)$ requires an anti-Markovnikov hydration followed by the conversion of the primary alcohol to an alkyl chloride.Step $1$: Hydroboration-oxidation of propene using $(i) (BH_3)_2$ and $(ii) H_2O_2 / OH^-$ yields propan-$1$-ol $(CH_3-CH_2-CH_2-OH)$.Step $2$: The conversion of propan-$1$-ol to $1$-chloropropane is typically achieved using $HCl$ in the presence of a catalyst like $ZnCl_2$ (Lucas reagent) or other chlorinating agents. Although primary alcohols react slowly with Lucas reagent,the sequence provided in option $A$ represents the standard synthetic route for this transformation.

Which of the following sequence of reagents converts propene to $1$-chloropropane?

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