(C) The amount of solute in grams is calculated using the formula: $\text{Mass} = \text{Molarity} (M) \times \text{Volume} (V \text{ in } L) \times \t

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$C$. $0.5 \ L$ of $1.0 \ M \ KMnO_4$ $(158 \ u)$

(C) The amount of solute in grams is calculated using the formula: $\text{Mass} = \text{Molarity} (M) \times \text{Volume} (V \text{ in } L) \times \text{Molar Mass} (MW)$.For $A$: $\text{Mass} = 0.25 \times 1.0 \times 106 = 26.5 \ g$.For $B$: $\text{Mass} = 0.2 \times 0.25 \times 142 = 7.1 \ g$.For $C$: $\text{Mass} = 1.0 \times 0.5 \times 158 = 79.0 \ g$.For $D$: $\text{Mass} = 0.5 \times 0.75 \times 60 = 22.5 \ g$.Comparing the values, $79.0 \ g$ is the highest amount. Therefore, option $C$ is correct.

Class 12 Chemistry Solutions Method of expressing concentration of solution

Medium

Which of the following solutions has the highest amount of solute (in grams)?

TS EAMCET 2025 All TS EAMCET

A
$A$. $1.0 \ L$ of $0.25 \ M \ Na_2CO_3$ $(106 \ u)$
B
$B$. $0.25 \ L$ of $0.2 \ M \ Na_2SO_4$ $(142 \ u)$
C
$C$. $0.5 \ L$ of $1.0 \ M \ KMnO_4$ $(158 \ u)$
D
$D$. $0.75 \ L$ of $0.5 \ M \ (NH_2)_2CO$ $(60 \ u)$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Solutions

Subtopic

Method of expressing concentration of solution

Previous Year

TS EAMCET 2025 Paper All TS EAMCET years →

The volume of ethyl alcohol (density $1.15 \text{ g/cc}$) that has to be added to prepare $100 \text{ cc}$ of $0.5 \text{ M}$ ethyl alcohol solution in water is: (in $\text{ cc}$)

DifficultWBJEE 2014

View Solution

What is the mass ratio of ethylene glycol $(C_2H_6O_2, \text{molar mass} = 62 g/mol)$ required for making $500 g$ of $0.25 m$ aqueous solution and $250 mL$ of $0.25 M$ aqueous solution?

DifficultJEE MAIN 2023

View Solution

$0.1 \ mol$ of $NaCl$ is dissolved in $100 \ g$ of water. The mole fraction of $NaCl$ is

EasyTS EAMCET 2018

View Solution

The molality of the solution prepared by dissolving $125 \ mL$ of pure methanol $(d = 0.8 \ g \ mL^{-1})$ in $375 \ g$ of ethanol is

Easy

View Solution

The molarity of a $70 \%$ (mass/mass) aqueous solution of a monobasic acid $(X)$ is $........... \ M$ (Nearest integer). Given: Density of aqueous solution of $(X)$ is $1.25 \ g \ mL^{-1}$,Molar mass of the acid is $70 \ g \ mol^{-1}$.

MediumJEE MAIN 2025

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Which of the following solutions has the highest amount of solute (in grams)?

Similar Questions

The volume of ethyl alcohol (density $1.15 \text{ g/cc}$) that has to be added to prepare $100 \text{ cc}$ of $0.5 \text{ M}$ ethyl alcohol solution in water is: (in $\text{ cc}$)

What is the mass ratio of ethylene glycol $(C_2H_6O_2, \text{molar mass} = 62 g/mol)$ required for making $500 g$ of $0.25 m$ aqueous solution and $250 mL$ of $0.25 M$ aqueous solution?

$0.1 \ mol$ of $NaCl$ is dissolved in $100 \ g$ of water. The mole fraction of $NaCl$ is

The molality of the solution prepared by dissolving $125 \ mL$ of pure methanol $(d = 0.8 \ g \ mL^{-1})$ in $375 \ g$ of ethanol is

The molarity of a $70 \%$ (mass/mass) aqueous solution of a monobasic acid $(X)$ is $........... \ M$ (Nearest integer). Given: Density of aqueous solution of $(X)$ is $1.25 \ g \ mL^{-1}$,Molar mass of the acid is $70 \ g \ mol^{-1}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module