Which of the following solutions will have th | vedclass

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(A) The elevation in boiling point is a colligative property,which depends on the van't Hoff factor $(i)$,representing the number of particles produce

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$0.1 \ M \ FeCl_3$

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(A) The elevation in boiling point is a colligative property,which depends on the van't Hoff factor $(i)$,representing the number of particles produced upon dissociation.For $0.1 \ M \ FeCl_3$,$i = 4$ $(Fe^{3+} + 3Cl^-)$.For $0.1 \ M \ BaCl_2$,$i = 3$ $(Ba^{2+} + 2Cl^-)$.For $0.1 \ M \ NaCl$,$i = 2$ $(Na^+ + Cl^-)$.For $0.1 \ M \ 	ext{urea}$,$i = 1$ (non-electrolyte).Since $0.1 \ M \ FeCl_3$ produces the maximum number of ions,it exhibits the highest elevation in boiling point and thus the highest boiling point.

Which of the following solutions will have the highest boiling point?

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