Which of the following solutions will have th | vedclass

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(D) The elevation in boiling point is a colligative property,which depends on the number of particles in the solution. $1\%$ solutions imply equal mas

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$1\%$ $CaCl_2$

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(D) The elevation in boiling point is a colligative property,which depends on the number of particles in the solution. $1\%$ solutions imply equal mass concentrations. Glucose and sucrose are non-electrolytes $(i = 1)$. $NaCl$ dissociates into $2$ ions $(Na^+ + Cl^-)$,so $i = 2$. $CaCl_2$ dissociates into $3$ ions $(Ca^{2+} + 2Cl^-)$,so $i = 3$. Since $CaCl_2$ produces the maximum number of particles per unit mass,it exhibits the highest boiling point elevation. Therefore,the correct option is $(D)$.

Which of the following solutions will have the highest boiling point?

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