Which of the following species has the highes | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The bond energy is directly proportional to the bond order. The bond order can be calculated using the formula: $	ext{Bond Order} = \frac{N_b - N

Vedclass · Accepted Answer

$O_{2}^{+}$

Vedclass · Answer

(B) The bond energy is directly proportional to the bond order. The bond order can be calculated using the formula: $	ext{Bond Order} = \frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons and $N_a$ is the number of antibonding electrons.$(A)$ $O_{2}^{2-}$: Total electrons = $18$. Configuration: $KK(\sigma 2s)^2, (\sigma^* 2s)^2, (\sigma 2p_z)^2, (\pi 2p_x)^2, (\pi 2p_y)^2, (\pi^* 2p_x)^2, (\pi^* 2p_y)^2$. Bond order = $\frac{10-8}{2} = 1$.$(B)$ $O_{2}^{+}$: Total electrons = $15$. Configuration: $KK(\sigma 2s)^2, (\sigma^* 2s)^2, (\sigma 2p_z)^2, (\pi 2p_x)^2, (\pi 2p_y)^2, (\pi^* 2p_x)^1$. Bond order = $\frac{10-5}{2} = 2.5$.$(C)$ $O_{2}^{-}$: Total electrons = $17$. Configuration: $KK(\sigma 2s)^2, (\sigma^* 2s)^2, (\sigma 2p_z)^2, (\pi 2p_x)^2, (\pi 2p_y)^2, (\pi^* 2p_x)^2, (\pi^* 2p_y)^1$. Bond order = $\frac{10-7}{2} = 1.5$.$(D)$ $O_{2}$: Total electrons = $16$. Configuration: $KK(\sigma 2s)^2, (\sigma^* 2s)^2, (\sigma 2p_z)^2, (\pi 2p_x)^2, (\pi 2p_y)^2, (\pi^* 2p_x)^1, (\pi^* 2p_y)^1$. Bond order = $\frac{10-6}{2} = 2$.Comparing the bond orders: $O_{2}^{+} (2.5) > O_{2} (2) > O_{2}^{-} (1.5) > O_{2}^{2-} (1)$.Since $O_{2}^{+}$ has the highest bond order,it has the highest bond energy.

Which of the following species has the highest bond energy?

Similar Questions

Which of the following best describes the given molecular orbital diagram?

Give the electron configuration,magnetic property,bond order,and energy diagram for the oxygen $(O_2)$ molecule.

Assertion : $C_2$ contains two $\pi$ bonds.
Reason : $C_2$ is diamagnetic in nature.

Arrange the following in the increasing order of their bond order: $O_{2}, O_{2}^{+}, O_{2}^{-}, O_{2}^{2-}$

Arrange the molecules $B_2, He_2, N_2$ and $C_2$ in the increasing order of their bond order values.

Vedclass Test Series

Exam Paper Generator

Online Exam Module