Which of the following statement(s) is(are) c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B, C) Statement $A$ is incorrect because for a very dilute acid solution, the contribution of $H^+$ ions from water cannot be neglected. The $pH$ of

Vedclass · Accepted Answer

The conjugate base of $H_2PO_4^-$ is $HPO_4^{2-}$

Vedclass · Answer

(B, C) Statement $A$ is incorrect because for a very dilute acid solution, the contribution of $H^+$ ions from water cannot be neglected. The $pH$ of $1.0 	imes 10^{-8} \ M$ $HCl$ is approximately $6.98$, not $8$.Statement $B$ is correct because the conjugate base is formed by the removal of one proton $(H^+)$ from the acid: $H_2PO_4^- ightarrow H^+ + HPO_4^{2-}$.Statement $C$ is correct because the autoprotolysis of water is an endothermic process $(\Delta H > 0)$, so the equilibrium constant $K_w$ increases with an increase in temperature.Statement $D$ is incorrect because at the half-neutralization point of a weak acid, the concentration of the acid equals the concentration of its conjugate base $([HA] = [A^-])$. According to the Henderson-Hasselbalch equation, $pH = pK_a + \log(\frac{[A^-]}{[HA]})$, which simplifies to $pH = pK_a$.

Which of the following statement(s) is(are) correct?

Similar Questions

The moles of $H^{+}$ from $H_2O$ alone in a $1 \ L$,$\sqrt{5} \times 10^{-7} \ M$ $HCl$ solution at $25 \ ^\circ C$ is ( $\sqrt{5} = 2.23$ )

For a weak acid $HCN$ at $25 \, ^\circ C$,which of the following statements is correct?

For the equilibrium $2H_2O \rightleftharpoons H_3O^{+} + OH^{-}$,the value of $\Delta G^o$ at $298 \ K$ is approximately ....... $kJ \ mol^{-1}$.

$20 \ mL$,$0.1 \ M \ HA$ $[(K_b)_{A^-} = 10^{-10}]$ is titrated against $0.2 \ M \ NaOH$. Select the correct statement [Given : $\log 2 = 0.3, \log 3 = 0.48$ ]

Given,$pH$ of a solution $A$ is $3$ and it is mixed with another solution $B$ having $pH$ $2$. If both are mixed in equal volume,then the resultant $pH$ of the solution will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module