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(B) Aspartic acid is an acidic amino acid with three ionizable groups. The isoelectric point $(pI)$ is the $pH$ at which the molecule exists as a zwit

Vedclass · Accepted Answer

at $pH = 2.95$,aspartic acid shows no net migration towards any electrode

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(B) Aspartic acid is an acidic amino acid with three ionizable groups. The isoelectric point $(pI)$ is the $pH$ at which the molecule exists as a zwitterion with no net charge,resulting in no net migration during electrophoresis. For an acidic amino acid,the $pI$ is calculated using the two lowest $pK_a$ values: $pI = \frac{pK_1 + pK_2}{2} = \frac{2.0 + 3.90}{2} = 2.95$. At $pH = 1.0$ $(pH At $pH = 2.95$ $(pH = pI)$,the molecule has no net charge and shows no net migration. At $pH = 7.0$ and $pH = 9.0$ $(pH > pI)$,the molecule is negatively charged and migrates towards the $(+)$ electrode.

Which of the following statements correctly describes the migration aptitude of aspartic acid during electrophoresis?
$(pK_1 = 2.0, pK_2 = 3.90, pK_3 = 10.0)$
$HOOC-CH_2-CH(NH_2)-COOH$

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Which of the following statements correctly describes the migration aptitude of aspartic acid during electrophoresis? $(pK_1 = 2.0, pK_2 = 3.90, pK_3 = 10.0)$ $HOOC-CH_2-CH(NH_2)-COOH$