Which of the following statements is true regarding the $PCl_5$ molecule?
$(i)$ The two axial $P-Cl$ bonds in $PCl_5$ are longer than the three equatorial bonds.
$(ii)$ The axial bonds in $PCl_5$ are stronger than equatorial bonds.
$(iii)$ The axial bonds in $PCl_5$ are more stable than equatorial bonds.
$(iv)$ All five bonds in $PCl_5$ molecule are equivalent.
$(i)$ The two axial $P-Cl$ bonds in $PCl_5$ are longer than the three equatorial bonds.
$(ii)$ The axial bonds in $PCl_5$ are stronger than equatorial bonds.
$(iii)$ The axial bonds in $PCl_5$ are more stable than equatorial bonds.
$(iv)$ All five bonds in $PCl_5$ molecule are equivalent.
- A$(i)$
- B$(ii)$
- C$(iii)$
- D$(iv)$
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Similar Questions
Match the following:
List-$I$ List-$II$ $(a)$ $SF_6$ $(i)$ $sp^3d^2$ $(b)$ $PCl_5$ (ii) $sp^3d$ $(c)$ $XeF_4$ (iii) $sp^3d^3$ $(d)$ $IF_7$ (iv) $sp^3d^2$
The correct answer is:
| List-$I$ | List-$II$ |
| $(a)$ $SF_6$ | $(i)$ $sp^3d^2$ |
| $(b)$ $PCl_5$ | (ii) $sp^3d$ |
| $(c)$ $XeF_4$ | (iii) $sp^3d^3$ |
| $(d)$ $IF_7$ | (iv) $sp^3d^2$ |
The correct answer is:
Find the incorrect statement.
Medium
View SolutionExplain bond formation in $BCl_{3}$. It is a symmetrical trigonal molecule.
Which of the following types of hybridisation results in trigonal planar geometry?
What is the hybridization of the beryllium atom in beryllium fluoride $(BeF_2)$?
Easy
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