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(D) $1$. $A$ $\sigma$ bond is formed by head-on overlapping, while a $\pi$ bond is formed by lateral (sideways) overlapping.$2$. Lateral overlapping i

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The presence of a $\pi$ bond increases the bond length of a covalent bond.

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(D) $1$. $A$ $\sigma$ bond is formed by head-on overlapping, while a $\pi$ bond is formed by lateral (sideways) overlapping.$2$. Lateral overlapping is less effective than head-on overlapping, making the $\pi$ bond weaker than the $\sigma$ bond.$3$. $A$ $\pi$ bond can only form between atoms that are already bonded by a $\sigma$ bond.$4$. The formation of a $\pi$ bond increases the bond order, which results in a decrease in the bond length, not an increase. Therefore, statement $(d)$ is incorrect.

Which of the following statements regarding the $\pi$ bond is $NOT$ true?

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