Which of the following tetracarboxylic acids | vedclass

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(D) Heating $1,2-$dicarboxylic acids leads to the formation of cyclic anhydrides by the loss of a water molecule. For a tetracarboxylic acid to form a

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Both $(a)$ and $(b)$

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(D) Heating $1,2-$dicarboxylic acids leads to the formation of cyclic anhydrides by the loss of a water molecule. For a tetracarboxylic acid to form a di-anhydride,it must have two pairs of adjacent carboxylic acid groups. In benzene$-1,2,3,4-$tetracarboxylic acid,there are two pairs of adjacent $-COOH$ groups (at positions $1,2$ and $3,4$),allowing for the formation of a di-anhydride. In benzene$-1,2,4,5-$tetracarboxylic acid (pyromellitic acid),there are two pairs of adjacent $-COOH$ groups (at positions $1,2$ and $4,5$),which also allows for the formation of a di-anhydride. Therefore,both compounds can form di-anhydrides upon heating.

List-$I$	List-$II$
$(P)$ Etard reaction	$(1)$ Acetophenone $\xrightarrow{Zn-Hg, HCl}$
$(Q)$ Gattermann reaction	$(2)$ Toluene $\xrightarrow[(ii) SOCl_2]{(i) KMnO_4, KOH}$
$(R)$ Gattermann-Koch reaction	$(3)$ Benzene $\xrightarrow[\text{anhyd. } AlCl_3]{CH_3Cl}$
$(S)$ Rosenmund reduction	$(4)$ Aniline $\xrightarrow[273-278 \ K]{NaNO_2 / HCl}$
	$(5)$ Phenol $\xrightarrow[Zn, \Delta]{ }$

Which of the following tetracarboxylic acids forms a di-anhydride upon heating?

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