Which of the following will act as the best o | vedclass

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(A) In the $d$-block elements,the stability of the higher oxidation state increases down the group. $Cr$ is in the $3d$ series,$Mo$ is in the $4d$ ser

Vedclass · Accepted Answer

$CrO_3$

Vedclass · Answer

(A) In the $d$-block elements,the stability of the higher oxidation state increases down the group. $Cr$ is in the $3d$ series,$Mo$ is in the $4d$ series,and $W$ is in the $5d$ series. As we move down the group,the stability of the $+6$ oxidation state increases,meaning the tendency to get reduced decreases. Therefore,the oxidizing power decreases as we go down the group: $CrO_3 > MoO_3 > WO_3$. Thus,$CrO_3$ acts as the best oxidizing agent among the given options.

Column-$I$	Column-$II$
$A$. $Pb_3O_4$	$I$. Neutral oxide
$B$. $N_2O$	$II$. Acidic oxide
$C$. $Mn_2O_7$	$III$. Basic oxide
$D$. $Bi_2O_3$	$IV$. Mixed oxide

Which of the following will act as the best oxidizing agent?

Similar Questions

Match the formulas given in Column-$I$ with the type of oxide given in Column-$II$ and select the correct option:-

Column-$I$ Column-$II$

$A$. $Pb_3O_4$ $I$. Neutral oxide

$B$. $N_2O$ $II$. Acidic oxide

$C$. $Mn_2O_7$ $III$. Basic oxide

$D$. $Bi_2O_3$ $IV$. Mixed oxide

When an excess of $KI$ is added to a $CuSO_4$ solution and then $Na_2S_2O_3$ is added to the mixture,which of the following statements is incorrect?

Which of these statements is not true?

Explain the trends in $E_{M^{3+}/M^{2+}}^{o}$ electrode potential.

Which of the following orders is not correct?

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