Which of the following will be a coloured ion | vedclass

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(A, D) An ion is coloured if it has unpaired electrons in its $d$-orbitals,allowing for $d-d$ transitions.$1$. $Fe^{2+}$ $([Ar] 3d^6)$: Has $4$ unpair

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$Fe^{2+}$

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(A, D) An ion is coloured if it has unpaired electrons in its $d$-orbitals,allowing for $d-d$ transitions.$1$. $Fe^{2+}$ $([Ar] 3d^6)$: Has $4$ unpaired electrons. It is coloured.$2$. $Cu^{+}$ $([Ar] 3d^{10})$: Has no unpaired electrons. It is colourless.$3$. $Sc^{3+}$ $([Ar] 3d^0)$: Has no unpaired electrons. It is colourless.$4$. $Mn^{2+}$ $([Ar] 3d^5)$: Has $5$ unpaired electrons. It is coloured.Note: Both $Fe^{2+}$ and $Mn^{2+}$ are coloured. However,in many standard contexts,$Mn^{2+}$ is specifically noted for its distinct pale pink colour,and $Fe^{2+}$ is green. Given the options,both $A$ and $D$ are technically correct. If a single choice is required,$Mn^{2+}$ is often the standard answer for $d^5$ systems.

Which of the following will be a coloured ion?

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