Which of the following will not give the iodoform test?

Match the following reactions in List-$I$ with their products in List-$II$.

List-$I$ (Reaction)	List-$II$ (Product)
$A$. $\text{Ketone} + NaBH_4$	$I$. $1^\circ$-alcohol
$B$. $\text{Ester} + LiAlH_4$	$II$. $3^\circ$-alcohol
$C$. $RMgX + \text{Ketone}$	$III$. $2^\circ$-alcohol
	$IV$. $\text{Alkane}$

Observe the following set of reactions. What are $X, Y$ and $Z$ respectively?

The reaction sequence is as follows:
Benzene + $CH_3COCl$ $\xrightarrow{\text{Anhydrous } AlCl_3} (A)$ $\xrightarrow{(x)} \text{Ethylbenzene}$.
Reagent $(x)$ can be:

Considering the following reaction sequence,the correct statement$(s)$ is(are):
$A$. Compounds $P$ and $Q$ are carboxylic acids.
$B$. Compound $S$ decolorizes bromine water.
$C$. Compounds $P$ and $S$ react with hydroxylamine to give the corresponding oximes.
$D$. Compound $R$ reacts with dialkylcadmium to give the corresponding tertiary alcohol.

Consider the above reaction sequence and identify the product $B$.