Which of the following will not produce a precipitate with $AgNO_3$ solution?

  • A
    $F^{-}$
  • B
    $Br^{-}$
  • C
    $CO_3^{2-}$
  • D
    $PO_4^{3-}$

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Similar Questions

In salt analysis,$Cl^{-}$,$Br^{-}$,and $I^{-}$ are identified by adding dilute $HNO_3$ followed by $AgNO_3$ solution to the salt solution. Choose the correct statements from the following:
$A$. $Cl^{-}$ gives pale yellow precipitate.
$B$. $Br^{-}$ gives pale yellow precipitate which is partially soluble in $NH_4OH$.
$C$. $I^{-}$ gives yellow precipitate which is insoluble in $NH_4OH$.
$D$. $Cl^{-}$ gives white precipitate which is soluble in $NH_4OH$.
$E$. $I^{-}$ gives yellow precipitate which is insoluble in $NH_4OH$.
Choose the correct answer from the options given below $:-$

Match List-$I$ with List-$II$:
List-$I$ (Anion) List-$II$ (Gas evolved on reaction with dil. $H_2SO_4$)
$A. CO_3^{2-}$ $I$. Colourless gas which turns lead acetate paper black
$B. S^{2-}$ $II$. Colourless gas which turns acidified potassium dichromate solution green
$C. SO_3^{2-}$ $III$. Brown fumes which turn acidified $KI$ solution containing starch blue
$D. NO_2^{-}$ $IV$. Colourless gas evolved with brisk effervescence,which turns lime water milky

Choose the correct answer from the options given below:

Given below are two statements:
Statement-$I$: The gas liberated on warming a salt with dil $H_2SO_4$,turns a piece of paper dipped in lead acetate into black,it is a confirmatory test for sulphide ion.
Statement-$II$: In statement-$I$ the colour of paper turns black because of formation of lead sulphite.
In the light of the above statements,choose the most appropriate answer from the options given below:

The brown ring test is used to detect the presence of which ion?

In the brown ring test,the brown color for $NO_2^-$ and $NO_3^-$ is due to the formation of which complex ion?

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