Which of the following will not show optical | vedclass

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(D) For an allene $(>C=C=C < )$ to exhibit optical isomerism,the substituents on each terminal carbon atom must be different.
In the given opti

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$CH_3-CH=C=CH-Cl$

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(D) For an allene $(>C=C=C < )$ to exhibit optical isomerism,the substituents on each terminal carbon atom must be different.
In the given options:
$A$) $Cl-CH=C=CH-Cl$: The terminal carbons have substituents $(H, Cl)$ and $(H, Cl)$. This molecule has a plane of symmetry if the groups are in the same plane,but allenes are non-planar. However,if the terminal groups are identical ($Cl, H$ on both sides),it can show geometrical isomerism,but it is achiral due to a plane of symmetry in the planar conformation or center of symmetry. Wait,for allenes $abC=C=Cab$,if $a 
eq b$,it is optically active. Here,$a=Cl, b=H$. Both sides have $Cl$ and $H$. This molecule is achiral.
$B$) $Br-CH=C=CH-Br$: Similar to $A$,this is achiral.
$C$) $CH_3-CH=C=CH-CH_3$: Similar to $A$ and $B$,this is achiral.
$D$) $CH_3-CH=C=CH-Cl$: Here,one terminal carbon has $(CH_3, H)$ and the other has $(Cl, H)$. Since the groups on each terminal carbon are different ($CH_3 
eq H$ and $Cl 
eq H$),this molecule is chiral and will show optical isomerism.
Re-evaluating the question: The question asks which will $NOT$ show optical isomerism. Options $A, B,$ and $C$ all have identical groups on the terminal carbons,making them achiral. This suggests a potential error in the question or options. Assuming the question intended to ask which one $DOES$ show optical isomerism,the answer is $D$.

Which of the following will not show optical isomerism?

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