Which of the following will show optical isom | vedclass

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(B) For a molecule to show optical isomerism,it must be chiral,meaning it should not have a plane of symmetry or a center of symmetry.$A$. Isobutane $

Vedclass · Accepted Answer

$1-$chloro$-2-$methylbutane

Vedclass · Answer

(B) For a molecule to show optical isomerism,it must be chiral,meaning it should not have a plane of symmetry or a center of symmetry.$A$. Isobutane $(CH_3-CH(CH_3)_2)$ has a plane of symmetry.$B$. $1-$chloro$-2-$methylbutane $(CH_3-CH_2-CH(CH_3)-CH_2Cl)$ has a chiral carbon atom at the $C-2$ position,which is bonded to four different groups ($-H$,$-CH_3$,$-CH_2CH_3$,and $-CH_2Cl$). Thus,it exhibits optical isomerism.$C$. $CH_2=C=CH_2$ (allene) is achiral due to the presence of planes of symmetry.$D$. $1,4-$dimethylcyclohexane has a plane of symmetry in its most stable conformation.Therefore,the correct option is $B$.

Which of the following will show optical isomerism?

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