Which of the following would be the best synt | vedclass

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(B) $2,2-$dimethylpropanoic acid is $(CH_3)_3CCOOH$. To synthesize this,we need a tertiary alkyl halide precursor,specifically $2-$bromo$-2-$methylpro

Vedclass · Accepted Answer

Acetone reacting with $1. CH_3MgBr/H^+, 2. SOBr_2, 3. Mg/Et_2O, 4. CO_2/H^+$

Vedclass · Answer

(B) $2,2-$dimethylpropanoic acid is $(CH_3)_3CCOOH$. To synthesize this,we need a tertiary alkyl halide precursor,specifically $2-$bromo$-2-$methylpropane $(CH_3)_3CBr$. Starting with acetone $(CH_3)_2C=O$: $1.$ Reaction with $CH_3MgBr$ followed by $H^+$ gives $2-$methylpropan$-2-$ol $(CH_3)_3COH$. $2.$ Reaction with $SOBr_2$ converts the alcohol to $2-$bromo$-2-$methylpropane $(CH_3)_3CBr$. $3.$ Reaction with $Mg$ in $Et_2O$ forms the Grignard reagent $(CH_3)_3CMgBr$. $4.$ Reaction with $CO_2$ followed by $H^+$ yields $2,2-$dimethylpropanoic acid $(CH_3)_3CCOOH$. Thus,option $B$ is the correct synthesis.

Which of the following would be the best synthesis of $2,2-$dimethylpropanoic acid?

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