Which of the given methods cannot produce Cl_ | vedclass

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(D) $1$. Electrolysis of brine ($NaCl$ solution) produces $Cl_2$ gas at the anode: $2NaCl(aq) + 2H_2O(l) \rightarrow 2NaOH(aq) + H_2(g) + Cl_2(g)$.$2$

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Heating $KCl$ with conc. $H_2SO_4$

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(D) $1$. Electrolysis of brine ($NaCl$ solution) produces $Cl_2$ gas at the anode: $2NaCl(aq) + 2H_2O(l) \rightarrow 2NaOH(aq) + H_2(g) + Cl_2(g)$.$2$. Deacon's process involves the oxidation of $HCl$ by atmospheric oxygen in the presence of $CuCl_2$ catalyst to produce $Cl_2$: $4HCl + O_2 \xrightarrow{CuCl_2} 2Cl_2 + 2H_2O$.$3$. Heating $MnO_2$ with concentrated $HCl$ is a standard laboratory method to produce $Cl_2$: $MnO_2 + 4HCl \rightarrow MnCl_2 + 2H_2O + Cl_2$.$4$. Heating $KCl$ with concentrated $H_2SO_4$ produces $HCl$ gas,not $Cl_2$: $KCl + H_2SO_4 \rightarrow KHSO_4 + HCl(g)$. Therefore,this method cannot produce $Cl_2$.

Which of the given methods cannot produce $Cl_2$?

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