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(A) The reaction involves the selective reduction of a ketone group to a secondary alcohol in the presence of a cyano group $(-CN)$ and an alkene $(-C

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$NaBH_4$

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(A) The reaction involves the selective reduction of a ketone group to a secondary alcohol in the presence of a cyano group $(-CN)$ and an alkene $(-CH=CH_2)$ group.$NaBH_4$ is a selective reducing agent that reduces aldehydes and ketones to alcohols but does not reduce alkenes or cyano groups.$LiAlH_4$ is a strong reducing agent that would reduce the ketone,the cyano group,and potentially the alkene.Therefore,$NaBH_4$ is the correct reagent for this transformation.

Which of these reagents would accomplish the following reduction?
$NC-CH_2-CO-CH_2-CH=CH_2 \to NC-CH_2-CH(OH)-CH_2-CH=CH_2$

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Which of these reagents would accomplish the following reduction?$NC-CH_2-CO-CH_2-CH=CH_2 \to NC-CH_2-CH(OH)-CH_2-CH=CH_2$