Which one among the following cannot exhibit | vedclass

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(A) Enantiomerism is exhibited by molecules that are chiral,meaning they possess at least one chiral carbon atom (a carbon atom bonded to four differe

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Diphenyl methanol

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(A) Enantiomerism is exhibited by molecules that are chiral,meaning they possess at least one chiral carbon atom (a carbon atom bonded to four different groups).$1.$ Diphenyl methanol: The central carbon is bonded to one $H$ atom,one $OH$ group,and two identical phenyl groups. Since it has two identical groups,it is achiral and cannot exhibit enantiomerism.$2.$ $1-$Bromo$-2-$chlorobutane: The carbon at position $2$ is bonded to $H$,$Cl$,$CH_3$,and $CH_2Br$. All four groups are different,so it is chiral.$3.$ $2-$Butanol: The carbon at position $2$ is bonded to $H$,$OH$,$CH_3$,and $CH_2CH_3$. All four groups are different,so it is chiral.$4.$ Tartaric acid: It contains two chiral carbon atoms and can exist as enantiomers (e.g.,$(+)-$ and $(-)-$tartaric acid).Therefore,Diphenyl methanol cannot exhibit enantiomerism.

Which one among the following cannot exhibit enantiomerism?

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