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(B) The iodoform test is given by compounds containing a $CH_3CO-$ group (methyl ketones) or compounds that can be oxidized to such a group (like acet

Vedclass · Accepted Answer

$(C_6H_5)_2Cd \xrightarrow{CH_3COCl} C_6H_5COCH_3$

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(B) The iodoform test is given by compounds containing a $CH_3CO-$ group (methyl ketones) or compounds that can be oxidized to such a group (like acetaldehyde or secondary alcohols with a methyl group at the alpha position).$(A)$ $CH_3CH_2CH_2COC_6H_5$ (Butyrophenone): Does not have a $CH_3CO-$ group.$(B)$ $C_6H_5COCH_3$ (Acetophenone): This is a methyl ketone $(CH_3CO-C_6H_5)$,so it gives a positive iodoform test.$(C)$ $CH_2=CHCH_2COC_6H_5$: Does not have a $CH_3CO-$ group.$(D)$ $C_6H_5CH_2COC_2H_5$: Does not have a $CH_3CO-$ group.Thus,option $B$ is the correct answer.

Which one among the following reaction products gives the iodoform test?

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