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(D) The rate of an $S_{N}1$ reaction depends on the stability of the carbocation intermediate formed in the rate-determining step. The more stable the

Vedclass · Accepted Answer

$1,1-$Diphenylethyl bromide $(C_6H_5C(CH_3)(C_6H_5)Br)$

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(D) The rate of an $S_{N}1$ reaction depends on the stability of the carbocation intermediate formed in the rate-determining step. The more stable the carbocation,the faster the $S_{N}1$ reaction.Comparing the carbocations formed from the given substrates:$A$: Benzyl cation $(C_6H_5CH_2^+)$ - Stabilized by resonance with one phenyl ring.$B$: $1-$Phenylethyl cation $(C_6H_5CH^+CH_3)$ - Stabilized by resonance and the inductive effect of the methyl group.$C$: $2-$Phenylpropan$-2-$yl cation $(C_6H_5C^+(CH_3)_2)$ - Stabilized by resonance and two methyl groups.$D$: $1,1-$Diphenylethyl cation $(C_6H_5C^+(CH_3)C_6H_5)$ - Stabilized by resonance with two phenyl rings and the inductive effect of one methyl group.Since the carbocation in option $D$ is stabilized by resonance with two phenyl rings,it is the most stable among the given options. Therefore,it will undergo the fastest $S_{N}1$ reaction.

Which one among the following will undergo a faster $S_{N}1$ reaction?

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