Which one is correct for a high spin complex?

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Question

(B) In a coordination complex,the crystal field splitting energy $(\Delta_0)$ and the pairing energy $(P)$ determine the electronic configuration of t

Vedclass · Accepted Answer

$\Delta_0 < P$

Vedclass · Answer

(B) In a coordination complex,the crystal field splitting energy $(\Delta_0)$ and the pairing energy $(P)$ determine the electronic configuration of the metal ion.For a high spin complex,the crystal field splitting energy is less than the pairing energy $(\Delta_0 This means that electrons prefer to occupy higher energy orbitals rather than pairing up in the lower energy orbitals,resulting in a maximum number of unpaired electrons.Therefore,the correct condition is $\Delta_0 < P$.

List-$I$ (Complex)	List-$II$ ($CFSE$ in $\Delta_0$)
$A$. $[Ti(H_2O)_6]^{2+}$	$I$. $-1.2$
$B$. $[V(H_2O)_6]^{2+}$	$II$. $-0.8$
$C$. $[Mn(H_2O)_6]^{3+}$	$III$. $-0.6$
$D$. $[Fe(H_2O)_6]^{3+}$	$IV$. $0$

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List-$I$ (Complex) List-$II$ ($CFSE$ in $\Delta_0$)

$A$. $[Ti(H_2O)_6]^{2+}$ $I$. $-1.2$

$B$. $[V(H_2O)_6]^{2+}$ $II$. $-0.8$

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