Which one is the correct order of the size of | vedclass

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(D) The size of an atom or ion depends on the number of electrons and the effective nuclear charge. For the same element,the size order is $I^{-} > I

Vedclass · Accepted Answer

$I^{-} > I > I^{+}$

Vedclass · Answer

(D) The size of an atom or ion depends on the number of electrons and the effective nuclear charge. For the same element,the size order is $I^{-} > I > I^{+}$. $I^{-}$ has $54$ electrons,$I$ has $53$ electrons,and $I^{+}$ has $52$ electrons. As the number of electrons decreases for the same nuclear charge,the effective nuclear charge per electron increases,leading to a smaller size. Therefore,the correct order is $I^{-} > I > I^{+}$.

Ion	Radius $(pm)$
$Q^{a+}$	$53$
$X^{b+}$	$66$
$Y^{c+}$	$40$
$Z^{d+}$	$100$

Which one is the correct order of the size of the iodine species?

Similar Questions

Consider the following species: $N^{3-}, O^{2-}, F^{-}, Na^{+}, Mg^{2+}$ and $Al^{3+}$
$(a)$ What is common in them?
$(b)$ Arrange them in the order of increasing ionic radii.

Which one of the following indicates the correct order of atomic size of the given elements?

Observe the following data.
Ion Radius $(pm)$
$Q^{a+}$ $53$
$X^{b+}$ $66$
$Y^{c+}$ $40$
$Z^{d+}$ $100$
$Q^{a+}, X^{b+}, Y^{c+}, Z^{d+}$ are respectively

For $Na^{+}$,$Mg^{2+}$,$F^{-}$,and $O^{2-}$; the correct order of increasing ionic radii is

Ionic radii are

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