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(D) The freezing point depression is given by the formula $\Delta T_{f} = i 	imes K_{f} 	imes m$. Since $K_{f}$ and $m$ are constant for all solutio

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$Al_{2}(SO_{4})_{3}$

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(D) The freezing point depression is given by the formula $\Delta T_{f} = i 	imes K_{f} 	imes m$. Since $K_{f}$ and $m$ are constant for all solutions,$\Delta T_{f} \propto i$. The freezing point $(T_{f})$ is related to the depression as $T_{f} = T_{f}^{\circ} - \Delta T_{f}$,meaning $T_{f} \propto -i$. Therefore,the solution with the highest van't Hoff factor $(i)$ will have the lowest freezing point. For $C_{6}H_{12}O_{6}$ (non-electrolyte),$i = 1$. For $K_{2}SO_{4} ightarrow 2K^{+} + SO_{4}^{2-}$,$i = 3$. For $KI ightarrow K^{+} + I^{-}$,$i = 2$. For $Al_{2}(SO_{4})_{3} ightarrow 2Al^{3+} + 3SO_{4}^{2-}$,$i = 5$. Since $Al_{2}(SO_{4})_{3}$ has the highest value of $i = 5$,it will have the lowest freezing point.

Which one of the following $0.06 \ M$ aqueous solutions has the lowest freezing point?

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