Which one of the following complexes is an ou | vedclass

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(D) An outer orbital complex uses the outer $d$-orbitals (e.g.,$4d$) for hybridization,typically $sp^3d^2$.$1$. $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ is $3d^6$

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$[Ni(NH_3)_6]^{2+}$

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(D) An outer orbital complex uses the outer $d$-orbitals (e.g.,$4d$) for hybridization,typically $sp^3d^2$.$1$. $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ is $3d^6$. $CN^-$ is a strong field ligand,causing pairing. Hybridization is $d^2sp^3$ (inner orbital).$2$. $[Mn(CN)_6]^{4-}$: $Mn^{2+}$ is $3d^5$. $CN^-$ is a strong field ligand,causing pairing. Hybridization is $d^2sp^3$ (inner orbital).$3$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand for $Co^{3+}$,causing pairing. Hybridization is $d^2sp^3$ (inner orbital).$4$. $[Ni(NH_3)_6]^{2+}$: $Ni^{2+}$ is $3d^8$. $NH_3$ is a weak field ligand relative to $Ni^{2+}$. Hybridization is $sp^3d^2$ (outer orbital).Thus,$[Ni(NH_3)_6]^{2+}$ is an outer orbital complex.

List-$I$	List-$II$
$A. Ni(CO)_4$	$I. sp^3$
$B. [Ni(CN)_4]^{2-}$	$II. sp^3d^2$
$C. [Co(CN)_6]^{3-}$	$III. d^2sp^3$
$D. [CoF_6]^{3-}$	$IV. dsp^2$

Which one of the following complexes is an outer orbital complex?
Atomic no.: $Mn = 25, Fe = 26, Co = 27, Ni = 28$

Similar Questions

Match List-$I$ with List-$II$.

List-$I$ List-$II$

$A. Ni(CO)_4$ $I. sp^3$

$B. [Ni(CN)_4]^{2-}$ $II. sp^3d^2$

$C. [Co(CN)_6]^{3-}$ $III. d^2sp^3$

$D. [CoF_6]^{3-}$ $IV. dsp^2$

Choose the correct answer from the options given below.

The hybridisation of $Ni$,shape,and number of unpaired electrons present in $[NiCl_4]^{2-}$ are respectively:

Which of the following is/are correct for the complex $[Cu(NH_3)_4]^{2+}$?

What is the geometry of $[Ni(CO)_4]$?

Which of the following complexes does not match with the hybridization state of its metal ion?
$(i) [Ni(CO)_4], sp^3$
$(ii) [Ni(CN)_4]^{2-}, sp^3$
$(iii) [CoF_6]^{3-}, d^2sp^3$
$(iv) [Fe(CN)_6]^{3-}, sp^3d^2$

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Which one of the following complexes is an outer orbital complex?Atomic no.: $Mn = 25, Fe = 26, Co = 27, Ni = 28$