Which one of the following compounds is not c | vedclass

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(B) The colour of transition metal complexes is generally due to $d-d$ transitions,which require the presence of unpaired $d$-electrons. In $Na_2CdCl_

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$Na_2CdCl_4$

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(B) The colour of transition metal complexes is generally due to $d-d$ transitions,which require the presence of unpaired $d$-electrons. In $Na_2CdCl_4$,the cadmium ion is $Cd^{2+}$. The electronic configuration of $Cd$ $(Z=48)$ is $[Kr] 4d^{10} 5s^2$. Thus,$Cd^{2+}$ has the configuration $[Kr] 4d^{10}$. Since the $d$-subshell is completely filled,there are no unpaired electrons available for $d-d$ transitions,making the compound colourless. Therefore,the correct option is $(B)$.

List-$I$ (Coordination compounds)	List-$II$ (Number of unpaired electrons)
$A$. $[Cr(CN)_6]^{3-}$	$I$. $0$
$B$. $[Fe(H_2O)_6]^{2+}$	$II$. $3$
$C$. $[Co(NH_3)_6]^{3+}$	$III$. $2$
$D$. $[Ni(NH_3)_6]^{2+}$	$IV$. $4$

Which one of the following compounds is not coloured?

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