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(B) The reaction of $CH_3MgBr$ (excess) with phenyl acetate $(C_6H_5OCOCH_3)$ proceeds as follows:$1$. The first equivalent of $CH_3MgBr$ attacks the

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Phenyl acetate

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(B) The reaction of $CH_3MgBr$ (excess) with phenyl acetate $(C_6H_5OCOCH_3)$ proceeds as follows:$1$. The first equivalent of $CH_3MgBr$ attacks the carbonyl carbon of the ester,followed by the elimination of the phenoxide ion $(C_6H_5O^-)$ to form acetophenone $(C_6H_5COCH_3)$.$2$. The second equivalent of $CH_3MgBr$ attacks the carbonyl carbon of acetophenone to form a tertiary alkoxide intermediate.$3$. Upon hydrolysis,this intermediate yields $2$-phenylpropan-$2$-ol,which is a tertiary alcohol.Therefore,phenyl acetate is the most appropriate compound to yield a tertiary alcohol as the primary organic product.

Column-$I$ (Compound)	Column-$II$ (Major Product)
$A$. $1$-Methylcyclohexanol	$i$. $1$-Methylcyclohexene
$B$. Butan-$1$-ol	$ii$. But-$1$-ene
$C$. tert-Butyl alcohol	$iii$. Isobutylene
$D$. Butan-$2$-ol	$iv$. But-$2$-ene

Which one of the following compounds will provide a tertiary alcohol on reaction with excess of $CH_3MgBr$ followed by hydrolysis?

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