Which one of the following has a square plana | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The correct answer is $[PtCl_4]^{2-}$.$Pt$ is a $5d$ series element. For $5d$ series elements,the crystal field splitting energy is high,so even w

Vedclass · Accepted Answer

$[PtCl_4]^{2-}$

Vedclass · Answer

(C) The correct answer is $[PtCl_4]^{2-}$.$Pt$ is a $5d$ series element. For $5d$ series elements,the crystal field splitting energy is high,so even weak field ligands like $Cl^-$ can cause pairing of electrons.$Pt^{2+}$ has a $5d^8$ configuration. Due to the pairing of electrons,it undergoes $dsp^2$ hybridisation,resulting in a square planar geometry.In contrast,$[FeCl_4]^{2-}$,$[NiCl_4]^{2-}$,and $[CoCl_4]^{2-}$ involve $3d$ series metals where $Cl^-$ acts as a weak field ligand and cannot cause pairing. Thus,they undergo $sp^3$ hybridisation and exhibit tetrahedral geometry.

Which one of the following has a square planar geometry?

Similar Questions

How many unpaired electrons are present in the central metal ion of $[CoCl_4]^{2-}$?

Considering $H_2O$ as a weak field ligand,the number of unpaired electrons in $[Mn(H_2O)_6]^{2+}$ will be (Atomic number of $Mn = 25$).

Nickel $(Z = 28)$ combines with a uninegative monodentate ligand $X^{-}$ to form a paramagnetic complex $[NiX_4]^{-2}.$ The number of unpaired electron$(s)$ in the nickel and geometry of this complex ion are,respectively $:$

Which of the following is an incorrect pair?

The hybridization of $Ag^+$ in the linear complex $[Ag(NH_3)_2]^+$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module