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(A) $CCl_4$ is a symmetrical molecule. Therefore,the dipole moments of all four $C-Cl$ bonds cancel each other. Hence,its resultant dipole moment is z

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$(i)$

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(A) $CCl_4$ is a symmetrical molecule. Therefore,the dipole moments of all four $C-Cl$ bonds cancel each other. Hence,its resultant dipole moment is zero.In $CHCl_3$,the resultant of dipole moments of two $C-Cl$ bonds is opposed by the resultant of dipole moments of one $C-H$ bond and one $C-Cl$ bond. Since the resultant of one $C-H$ bond and one $C-Cl$ bond dipole moments is smaller than two $C-Cl$ bonds,the opposition is to a small extent. As a result,$CHCl_3$ has a small dipole moment of $1.08 \ D$.On the other hand,in case of $CH_2Cl_2$,the resultant of the dipole moments of two $C-Cl$ bonds is strengthened by the resultant of the dipole moments of two $C-H$ bonds. As a result,$CH_2Cl_2$ has a higher dipole moment of $1.60 \ D$ than $CHCl_3$. Thus,$CH_2Cl_2$ has the highest dipole moment.The increasing order of their dipole moments is: $CCl_4 < CHCl_3 < CH_2Cl_2$.

Which one of the following has the highest dipole moment?
$(i)$ $CH_2Cl_2$
$(ii)$ $CHCl_3$
$(iii)$ $CCl_4$

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Which one of the following has the highest dipole moment?$(i)$ $CH_2Cl_2$$(ii)$ $CHCl_3$$(iii)$ $CCl_4$