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(C) Molar conductivity is directly proportional to the number of ions produced upon dissociation in an aqueous solution.$1$. $[Pt(NH_3)_2 Cl_2] \right

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Potassium hexacyano ferrate $(II)$

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(C) Molar conductivity is directly proportional to the number of ions produced upon dissociation in an aqueous solution.$1$. $[Pt(NH_3)_2 Cl_2] \rightarrow$ Non-electrolyte ($0$ ions).$2$. $[Co(NH_3)_4 Cl_2]Cl \rightarrow [Co(NH_3)_4 Cl_2]^+ + Cl^-$ ($2$ ions).$3$. $K_4[Fe(CN)_6] \rightarrow 4K^+ + [Fe(CN)_6]^{4-}$ ($5$ ions).$4$. $[Cr(H_2O)_6]Cl_3 \rightarrow [Cr(H_2O)_6]^{3+} + 3Cl^-$ ($4$ ions).Since $K_4[Fe(CN)_6]$ produces the highest number of ions ($5$ ions),it exhibits the highest molar conductivity.

Which one of the following has the highest molar conductivity?

Similar Questions

Assertion : $NF_3$ is a weaker ligand than $N(CH_3)_3$.
Reason : $NF_3$ ionizes to give $F^{-}$ ions in aqueous solution.

The molar ionic conductances of the octahedral complexes:
$(I)$ $PtCl_4 \cdot 5NH_3$
$(II)$ $PtCl_4 \cdot 4NH_3$
$(III)$ $PtCl_4 \cdot 3NH_3$
$(IV)$ $PtCl_4 \cdot 2NH_3$
Follow the order $-$

Select the most stable complex.

Assign $A, B, C, D$ for the given type of reaction: $Fe(CN)_3 \downarrow + 3KCN \longrightarrow K_3[Fe(CN)_6]$

The correct increasing order of trans-effect of the following species is:

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