Which one of the following has the maximum number of unpaired electrons?

  • A
    $Mg^{2+}$
  • B
    $Ti^{3+}$
  • C
    $V^{3+}$
  • D
    $Fe^{2+}$

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Similar Questions

Number of unpaired electrons in $Mn^{2+}$ is

Match List-$I$ with List-$II$
List-$I$ Species List-$II$ Electronic distribution
$A$. $Cr^{2+}$ $I$. $3d^8$
$B$. $Mn^{+}$ $II$. $3d^3 4s^1$
$C$. $Ni^{2+}$ $III$. $3d^4$
$D$. $V^{+}$ $IV$. $3d^5 4s^1$

Choose the correct answer from the options given below:

The spin-only magnetic moment value of the ion among $Ti^{2+}$,$V^{2+}$,$Co^{3+}$,and $Cr^{2+}$ that acts as a strong oxidizing agent in aqueous solution is .......... $BM$ (nearest integer).
(Given atomic numbers: $Ti = 22, V = 23, Cr = 24, Co = 27$)

Write down the electronic configuration of:
$(i) Cr^{3+}$
$(ii) Pm^{3+}$
$(iii) Cu^{+}$
$(iv) Ce^{4+}$
$(v) Co^{2+}$
$(vi) Lu^{2+}$
$(vii) Mn^{2+}$
$(viii) Th^{4+}$

Choose the correct statement. $Fe^{3+}$ ion is more stable than $Fe^{2+}$ ion because

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