Which one of the following ions has the same | vedclass

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(B) The electronic configuration of Vanadium $(Z=23)$ is $[Ar] 3d^3 4s^2$.For $V^{3+}$,the configuration is $[Ar] 3d^2 4s^0$,which contains $2$ unpair

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$Ni^{2+}$

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(B) The electronic configuration of Vanadium $(Z=23)$ is $[Ar] 3d^3 4s^2$.For $V^{3+}$,the configuration is $[Ar] 3d^2 4s^0$,which contains $2$ unpaired electrons.Now,let us check the options:$A) Fe^{3+} (Z=26): [Ar] 3d^5 4s^0 \Rightarrow 5$ unpaired electrons.$B) Ni^{2+} (Z=28): [Ar] 3d^8 4s^0 \Rightarrow 2$ unpaired electrons.$C) Mn^{2+} (Z=25): [Ar] 3d^5 4s^0 \Rightarrow 5$ unpaired electrons.$D) Cr^{3+} (Z=24): [Ar] 3d^3 4s^0 \Rightarrow 3$ unpaired electrons.Thus,$Ni^{2+}$ has the same number of unpaired electrons as $V^{3+}$.

Which one of the following ions has the same number of unpaired electrons as those present in $V^{3+}$ ion?

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