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(C) For $BeCl_2$: The central atom $Be$ has $2$ valence electrons and forms $2$ bonds with $Cl$. It undergoes $sp$-hybridization and has a linear shap

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$BCl_3$,$sp^2$,triangular planar

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(C) For $BeCl_2$: The central atom $Be$ has $2$ valence electrons and forms $2$ bonds with $Cl$. It undergoes $sp$-hybridization and has a linear shape.For $BCl_3$: The central atom $B$ has $3$ valence electrons and forms $3$ bonds with $Cl$. It undergoes $sp^2$-hybridization and has a trigonal planar (triangular planar) shape.Therefore,the correct set is $BCl_3$,$sp^2$,triangular planar.

Which one of the following is a correct set with respect to molecule,hybridisation,and shape?

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