Which one of the following is an outer orbita | vedclass

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(A) To determine the nature of the complexes,we analyze their electronic configurations and hybridization:$1$. $[Ni(NH_3)_6]^{2+}$: $Ni^{2+}$ is $3d^8

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$[Ni(NH_3)_6]^{2+}$

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(A) To determine the nature of the complexes,we analyze their electronic configurations and hybridization:$1$. $[Ni(NH_3)_6]^{2+}$: $Ni^{2+}$ is $3d^8$. It forms an outer orbital complex ($sp^3d^2$ hybridization) with $2$ unpaired electrons,making it paramagnetic.$2$. $[Zn(NH_3)_6]^{2+}$: $Zn^{2+}$ is $3d^{10}$. It is diamagnetic as there are no unpaired electrons.$3$. $[Cr(NH_3)_6]^{3+}$: $Cr^{3+}$ is $3d^3$. It forms an inner orbital complex ($d^2sp^3$ hybridization) and is paramagnetic,but it is not an outer orbital complex.$4$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $3d^6$. In the presence of strong field ligand $NH_3$,it forms an inner orbital complex ($d^2sp^3$ hybridization) and is diamagnetic.Therefore,$[Ni(NH_3)_6]^{2+}$ is the correct answer.

Which one of the following is an outer orbital complex and exhibits paramagnetic behavior?

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