Which one of the following is correct about t | vedclass

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(A) The stability of oxidation states in Group $14$ elements is governed by the inert pair effect. As we move down the group from $C$ to $Pb$,the stab

Vedclass · Accepted Answer

$Pb^{2+} > Pb^{4+}$

Vedclass · Answer

(A) The stability of oxidation states in Group $14$ elements is governed by the inert pair effect. As we move down the group from $C$ to $Pb$,the stability of the $+4$ oxidation state decreases,while the stability of the $+2$ oxidation state increases due to the poor shielding effect of $d$ and $f$ orbitals. For $Pb$ (Lead),the $+2$ oxidation state is more stable than the $+4$ oxidation state. Therefore,the correct order is $Pb^{2+} > Pb^{4+}$.

Which one of the following is correct about the stability of the given ions?

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