Which one of the following is different from | vedclass

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(C) Hydrolysis of a compound depends on the presence of vacant $d$-orbitals or the ability to expand the octet.$CCl_4$ does not undergo hydrolysis bec

Vedclass · Accepted Answer

$BF_3$

Vedclass · Answer

(C) Hydrolysis of a compound depends on the presence of vacant $d$-orbitals or the ability to expand the octet.$CCl_4$ does not undergo hydrolysis because carbon lacks vacant $d$-orbitals and is sterically hindered.$NF_3$ does not undergo hydrolysis because nitrogen lacks vacant $d$-orbitals and the $N-F$ bond is very strong.$SF_6$ does not undergo hydrolysis due to steric hindrance by six fluorine atoms around the sulfur atom,which prevents the attack of water molecules.$BF_3$ undergoes hydrolysis to form $H_3BO_3$ and $HBF_4$ because boron has a vacant $p$-orbital and can accept a lone pair from water.Therefore,$BF_3$ is different from the others as it readily undergoes hydrolysis.

Which one of the following is different from others with respect to hydrolysis?

Similar Questions

Which of the following are isoelectronic species?
$I. CH_{3}^{+}$,$II. H_{3}O^{+}$,$III. NH_{3}$,$IV. CH_{3}^{-}$

The formal charges of atoms $(1)$,$(2)$ and $(3)$ in the ion $[\underset{(1)}{O}=\underset{(2)}{N}=\underset{(3)}{O}]^{+}$ are:

The number of ionic,covalent,and coordinate bonds in $NH_4Cl$ are respectively:

The bond length of $C-F$ in $CH_3F$ molecule is (in $pm$)

Choose the correct order for the given property.
$M.P. \to$ Melting Point; $S \to$ Solubility

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