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(D) Optical isomerism is exhibited by coordination compounds that lack a plane of symmetry or a center of inversion.$1$. $cis-[Pt(NH_3)_2Cl_2]$ and $t

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$cis-[Co(en)_2Cl_2]^+$

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(D) Optical isomerism is exhibited by coordination compounds that lack a plane of symmetry or a center of inversion.$1$. $cis-[Pt(NH_3)_2Cl_2]$ and $trans-[Pt(NH_3)_2Cl_2]$ are square planar complexes,which generally do not exhibit optical isomerism due to the presence of a molecular plane of symmetry.$2$. $trans-[Co(en)_2Cl_2]^+$ has a plane of symmetry passing through the $Co$ atom and the two $Cl$ atoms,making it achiral.$3$. $cis-[Co(en)_2Cl_2]^+$ lacks a plane of symmetry and a center of inversion,meaning it exists as a pair of non-superimposable mirror images (enantiomers). Therefore,it exhibits optical isomerism.

Complex	Structure and magnetic property
$i$. $NiCl_4^{2-}$	$p$. tetrahedral and diamagnetic
$ii$. $Ni(CO)_4$	$q$. tetrahedral and paramagnetic
$iii$. $PtCl_4^{2-}$	$r$. square planar and diamagnetic
$iv$. $Ni(CN)_4^{2-}$	$s$. square planar and paramagnetic

Which one of the following is expected to exhibit optical isomerism $(en = \text{ethylenediamine})$?

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